>>> lst = ['jiang', 'xun', 'zhi']
# len() 列表长度
>>> len(lst)
3
>>> alst = ['gong', 'yu', 'xin']
# "+" 连接两个序列
>>> lst + alst
['jiang', 'xun', 'zhi', 'gong', 'yu', 'xin']
# "*" 重复序列元素
>>> lst * 3
['jiang', 'xun', 'zhi', 'jiang', 'xun', 'zhi', 'jiang', 'xun', 'zhi']
# 序列是否包含该元素
>>> "jiang" in lst
True
# 按照元素字典顺序进行比较
>>> max(lst)
'zhi'
>>> min(lst)
'jiang'
# 修改列表元素
# list.append(x) 向列表中追加元素 x
>>> cities = ['harbin', 'changchun']
>>> cities[1] = 'beijing'
>>> cities
['harbin', 'beijing']
>>> cities.append('shanghai')
>>> cities
['harbin', 'beijing', 'shanghai']
# list.extend([L]) 向列表中追加列表 L 的元素
>>> la = [1, 2, 3]
>>> lb = ['jiang', 'gong']
>>> la.extend(lb)
>>> la
[1, 2, 3, 'jiang', 'gong']
>>> lb
['jiang', 'gong']
# append() 和 extend() 的区别
# append() 是整建制的追加
# extend() 是个体化扩编
>>> alst = [1, 2, 3]
>>> blst = [1, 2, 3]
>>> clst = ["jiang", "gong"]
>>> alst.append(clst)
>>> alst
[1, 2, 3, ['jiang', 'gong']]
>>> len(alst)
4
>>> blst.extend(clst)
>>> blst
[1, 2, 3, 'jiang', 'gong']
>>> len(blst)
5
# list.count(x) x 元素出现次数
>>> la = [1, 2, 2, 1, 3, 1]
>>> la.count(1)
3
# list.insert(i, x) 将 x 插入到索引是 i 的元素前面
>>> lst = ["gong", "xin"]
>>> lst.insert(1, "yu")
>>> lst
['gong', 'yu', 'xin']
# list.remove(x) 删除第一次出现的 x 元素，无返回值
>>> lst = ["python", "c++", "python", "java"]
>>> lst.remove("python")
>>> lst
['c++', 'python', 'java']
# list.pop([i]) 删除索引为 i 的元素，并将删除元素作为返回值。
# i 为空则删除列表最后一个
>>> lst.pop(1)
'python'
>>> lst
['c++', 'java']
# list.reverse(L) 将元素顺序反转，不返回值
>>> a = [8, 3, 1, 4, 3, 0]
>>> a.reverse()
>>> a
[0, 3, 4, 1, 3, 8]
# reversed(L) 实现对列表的反向迭代
>>> b = reversed(a)
>>> list(b)
[8, 3, 1, 4, 3, 0]
>>> b
<list_reverseiterator object at 0x0000015DFC053710>
# list.sort() 对列表进行排序
>>> a.sort()
>>> a
[0, 1, 3, 3, 4, 8]
# 从大到小排序
>>> a.sort(reverse = True)
>>> a
[8, 4, 3, 3, 1, 0]
# 按字符串长度排序
>>> lst = ["java", "python", "c++", "basic", "pascal"]
>>> lst.sort(key = len)
>>> lst
['c++', 'java', 'basic', 'python', 'pascal']
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